Đáp án:
`↓↓↓`
Giải thích các bước giải:
`a) (x+5)^2-(x+4)(x-4)`
`=x^2+10x+25-(x^2-16)`
`=x^2+10x+25-x^2+16`
`=(x^2-x^2)+10x+(25+16)`
`=10x+41`
`b)` Ta có: `x^3-y^3-9xy`
`=(x-y)(x^2+xy+y^2)-9xy`
`=3(x^2+xy+y^2)-9xy`
`=3x^2+3xy+3y^2-9xy`
`=3x^2+3y^2-6xy`
`=3(x^2-2xy+y^2)`
`=3(x-y)^2=3.3^2=27`
`c) x^2+4y^2-2x-4y+2=0`
`=> (x^2-2x+1)+(4y^2-4y+1)=0`
`=> (x-1)^2+(2y-1)^2=0`
`=>` $\left\{\begin{matrix}(x-1)^2=0& \\(2y-1)^2=0& \end{matrix}\right.$
`=>` $\left\{\begin{matrix}x=1& \\y=\dfrac{1}{2}& \end{matrix}\right.$