Gọi các góc $A,B,C $ là $a,b,c$
Và : $a+b+c= 180^o$
Ta có :
$\dfrac{a}{3}=\dfrac{b}{2}=\dfrac{c}{1}$ = $\dfrac{a+b+c}{3+2+1}$ = $30$
$\dfrac{a}{3}=30 ⇒ a = 30.3 = 90$
$\dfrac{b}{2}=30 => b = 30.2 = 60$
$\dfrac{c}{1}=30=> c = 30$
⇔ Số đo các góc $A,B,C$ lần lượt là : $90^o, 60^o,30^o$
@Magic_
Theo đề bài ta có :
`∠A/3 = ∠B/2 = ∠C/1`
Áp dụng tính chất dãy tỉ số bằng nhau , ta được :
`\frac{∠A}{3} =\frac{∠B}{2} =\frac{∠C}{1} = \frac{∠A+∠B+∠C}{3+2+1} = \frac{180^o}{6} = 30^o`
Suy ra :
`∠A = 90^o`
`∠B = 60^o`
`∠C = 30^o`
Vậy `(∠A ; ∠B ; ∠C) = (90^o ; 60^o ; 30^o)`
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