Tính các tổng sau
a) \(A=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\ldots +\frac{1}{99.100}\)
b) \(B=\frac{1}{2.5}+\frac{1}{5.8}+\frac{1}{8.11}+...+\frac{1}{32.35}\)
A.a) \(\frac{{99}}{{100}}\)b) \(\frac{{11}}{{70}}\)
B.a) \(\frac{{99}}{{100}}\)b) \(\frac{{13}}{{70}}\)
C.a) \(\frac{{99}}{{105}}\)b) \(\frac{{11}}{{70}}\)
D.a) \(\frac{{99}}{{100}}\)b) \(\frac{{21}}{{70}}\)
Loga
Hóa Học lớp 12
