$y'$=$\dfrac{(3x-2)'\sqrt[]{2x+5}-(\sqrt[]{2x+5})'.(3x-2) }{2x+5}$
=$\dfrac{3\sqrt[]{2x+5}-\dfrac{2}{2 \sqrt[]{2x+5}} }{2x+5}$
=$\dfrac{3x+17}{\sqrt[]{(2x+5)^3}}$
16 $y'$=$\dfrac{(3x^2+2x-1)'(x^2-1)-(x^2-1)'(3x^2+2x-1)}{(x^2-1)^2}$
$y'$=$\dfrac{(6x+2)(x^2-1)-2x(3x^2+2x-1)}{(x^2-1)^2}$
$y'$=$\dfrac{6x^3-6x+2x62-2-6x^3-4x^2+2x}{(x^2-1)^2}$
$y'$=$\dfrac{-2x^2-4x-2}{(x^2-1)^2}$
$y'$=$\dfrac{-2}{(x-1)^2}$
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