Đáp án: a/ y'= (2sin3x)'(cos2x)+(sin3x)(cos2x)'
y' = 2((3cos3x)(cos2x)) - (2(sin2x)(sin3x))
y' = 2(3cos3x.cos2x - 2sin2x.sin3x)
( 6cos3x.cos2x - 4sin2x.sin3x)
b/ y' = 2(x^3-2x^2).(x^3-2x^2)'
y' = 2(x^3-2x^2).(3x^2-4x)
c/ y' = (-3cos3x)' - (4cos2x)'
y' = -(-9sin3x - (-8sin2x))
y' = 9sin3x + 8sin2x