Tính đạo hàm của hàm số \(y = {\left( {\dfrac{{2018}}{x}} \right)^{2019}}.{\left( {\dfrac{x}{{2019}}} \right)^{2018}}\)tại điểm \(x = 1.\)
A.\( - \dfrac{{{{2018}^{2019}}}}{{{{2019}^{2018}}}}\)
B.\( - \dfrac{{{{2019}^{2018}}}}{{{{2018}^{2019}}}}\)
C.\(\dfrac{{{{2019}^{2018}}}}{{{{2018}^{2019}}}}\)
D.\(\dfrac{{{{2018}^{2019}}}}{{{{2019}^{2018}}}}\)
A.\( - \dfrac{{{{2018}^{2019}}}}{{{{2019}^{2018}}}}\)
B.\( - \dfrac{{{{2019}^{2018}}}}{{{{2018}^{2019}}}}\)
C.\(\dfrac{{{{2019}^{2018}}}}{{{{2018}^{2019}}}}\)
D.\(\dfrac{{{{2018}^{2019}}}}{{{{2019}^{2018}}}}\)
Loga
Hóa Học lớp 12
