Em tham khảo nha:
\(\begin{array}{l}
*{C_5}{H_{12}}:\\
k = \dfrac{{2 \times 5 + 2 - 12}}{2} = 0\\
C{H_3} - C{H_2} - C{H_2} - C{H_2} - C{H_3}:pen\tan \\
C{H_3} - CH(C{H_3}) - C{H_2} - C{H_3}:2 - metyl\,bu\tan \\
C{H_3} - C{(C{H_3})_2} - C{H_3}:2,2 - \dim etyl\,propan\\
*{C_6}{H_{14}}\\
k = \dfrac{{2 \times 6 + 2 - 14}}{2} = 0\\
C{H_3} - C{H_2} - C{H_2} - C{H_2} - C{H_2} - C{H_3}:h{\rm{ex}}an\\
C{H_3} - CH(C{H_3}) - C{H_2} - C{H_2} - C{H_3}:2 - metyl\,pen\tan \\
C{H_3} - C{(C{H_3})_2} - C{H_2} - C{H_3}:2,2 - \dim etyl\,bu\tan \\
C{H_3} - CH(C{H_3}) - CH(C{H_3}) - C{H_3}:2,3 - \dim etyl\,bu\tan \\
*{C_4}{H_8}:\\
k = \dfrac{{2 \times 4 + 2 - 8}}{2} = 1\\
C{H_2} = CH - C{H_2} - C{H_3}:but - 1 - en\\
C{H_3} - CH = CH - C{H_3}:but - 2 - en\\
C{H_2} = C(C{H_3}) - C{H_3}:2 - metyl\,propen\\
*{C_4}{H_6}:\\
k = \dfrac{{2 \times 4 + 2 - 6}}{2} = 2\\
CH \equiv C - C{H_2} - C{H_3}:but - 1 - in\\
C{H_3} - C \equiv C - C{H_3}:but - 2 - in\\
C{H_2} = CH - CH = C{H_3}:buta - 1,3 - dien\\
C{H_2} = C = CH - C{H_3}:buta - 1,2 - dien
\end{array}\)
