Đáp án:
$\begin{array}{l}
A = 2\left| {2x - 1} \right| - 3\left| {1 - x} \right|\\
= 2.\left| {2.2 - 1} \right| - 3.\left| {1 - 2} \right|\\
= 2.\left| 3 \right| - 3\left| { - 1} \right|\\
= 2.3 - 3.1\\
= 3\\
B = 2{x^2} - 4\left| {x + 1} \right|\\
= 2.{\left( {\frac{{ - 1}}{2}} \right)^2} - 4.\left| { - \frac{1}{2} + 1} \right|\\
= 2.\frac{1}{4} - 4.\left| {\frac{1}{2}} \right|\\
= \frac{1}{2} - 4.\frac{1}{2}\\
= - \frac{3}{2}\\
C = 2\left| {x - 1} \right| + \frac{1}{2}\left| {3y + 1} \right|\\
= 2.\left| { - 5 - 1} \right| + \frac{1}{2}.\left| {3.\left( { - 3} \right) + 1} \right|\\
= 2.\left| { - 6} \right| + \frac{1}{2}.\left| { - 8} \right|\\
= 2.6 + \frac{1}{2}.8\\
= 12 + 4 = 16\\
D = 2\left| {2x - 5} \right| - \left| {5 - 6x} \right|\\
= 2.\left| {2.\left( { - 2} \right) - 5} \right| - \left| {5 - 6.\left( { - 2} \right)} \right|\\
= 2.\left| { - 9} \right| - \left| {5 + 12} \right|\\
= 2.9 - 17\\
= 1
\end{array}$
