Đáp án:
\( {m_{{C_6}{H_{12}}{O_6}}} = 22,5{\text{ gam}}\)
Giải thích các bước giải:
Phản ứng xảy ra:
\({C_6}{H_{12}}{O_6}\xrightarrow{{men}}2{C_2}{H_5}OH + 2C{O_2}\)
Ta có:
\({n_{{C_2}{H_5}OH}} = \frac{{9,2}}{{46}} = 0,2{\text{ mol}}\)
\( \to {n_{{C_6}{H_{12}}{O_6}{\text{ lt}}}} = \frac{1}{2}{n_{{C_2}{H_5}OH}} = \frac{1}{2}.0,2 = 0,1{\text{ mol}}\)
\( \to {n_{{C_6}{H_{12}}{O_6}}} = \frac{{0,1}}{{80\% }} = 0,125{\text{ mol}}\)
\( \to {m_{{C_6}{H_{12}}{O_6}}} = 0,125.180 = 22,5{\text{ gam}}\)
