nAl=27/27=1mol
2Al+3ZnCl2→2AlCl3+3Zn
1 1 1,5
mAlCl3=1.133,5=133,5g
mZn=1,5.65=97,5g
Ta có
2Al + 3ZnCl2→2AlCl3 +3Zn ( do kim loại mạnh đẩy kim loại yếu)
nAl=27/27=1(mol)
Theo PTHH nên ⇒nAlCl3=1(mol)
⇒nZn=1,5 mol
⇒mAlCl3=1*133.5=133.5(gam) (sản phẩm)
⇒mZn=1,5*65=97.5(gam) (sản phẩm)
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