Đáp án:
`\sqrt{6-sqrt{11}}/(sqrt{22}-sqrt2)+6/sqrt2-3/(sqrt2+1)`
`=(\sqrt2.sqrt{6-sqrt{11}})/(sqrt2(sqrt{22}-sqrt2))+(3.2)/sqrt2-(3(sqrt2-1))/((sqrt2+1)(sqrt2-1))`
`=(sqrt{12-2sqrt{11}})/(sqrt2(sqrt{22}-sqrt2))+3sqrt2-(3(sqrt2-1))`
`=sqrt{11-2sqrt{11}+1}/(sqrt2.sqrt2(sqrt{11}-1))+3sqrt2-3sqrt2+3`
`=sqrt{(sqrt{11}-1)^2}/(2(sqrt{11}-1))+3`
`=(sqrt{11}-1)/(2(sqrt{11}-1))+3`
`=1/2+3=7/2`.