Đáp án đúng: A
Giải chi tiết:Ta có:
\(\begin{array}{l}F\left( x \right) = - 5{x^3} + 6{x^2} + 3x - 1\\G\left( x \right) = - 5{x^3} + 6{x^2} + 4x + 2\\M\left( x \right) = F\left( x \right) - G\left( x \right)\\ = - 5{x^3} + 6{x^2} + 3x - 1 - \left( { - 5{x^3} + 6{x^2} + 4x + 2} \right)\\ = - 5{x^3} + 6{x^2} + 3x - 1 + 5{x^3} - 6{x^2} - 4x - 2\\ = \left( { - 5{x^3} + 5{x^3}} \right) + \left( {6{x^2} - 6{x^2}} \right) + \left( {3x - 4x} \right) + \left( { - 1 - 2} \right)\\ = - x - 3\end{array}\)
\(\begin{array}{l}{\rm N}\left( x \right) = F\left( x \right) + G\left( x \right)\\\,\,\,\,\,\,\,\,\,\,\,\, = - 5{x^3} + 6{x^2} + 3x - 1 + \left( { - 5{x^3} + 6{x^2} + 4x + 2} \right)\\\,\,\,\,\,\,\,\,\,\,\,\, = \,\,\left( { - 5{x^3} - 5{x^3}} \right) + \left( {6{x^2} + 6{x^2}} \right) + \left( {3x + 4x} \right) + \left( {2 - 1} \right)\\\,\,\,\,\,\,\,\,\,\,\,\, = \, - 10{x^3} + 12{x^2} + 7x + 1\end{array}\)
Chọn A