Tính \(\mathop {\lim }\limits_{x \to 2} \frac{{{x^3} - 6{x^2} + 11x - 6}}{{{x^2} - 4}}\)bằng?
A.\(\frac{1}{4}.\)
B. \(\frac{1}{3}.\)
C.\( - \frac{1}{4}.\)
D.\( - \frac{1}{3}.\)
A.\(\frac{1}{4}.\)
B. \(\frac{1}{3}.\)
C.\( - \frac{1}{4}.\)
D.\( - \frac{1}{3}.\)
Loga
Hóa Học lớp 12
