a) $\displaystyle\int\dfrac{2x+5}{2x-2}dx$
$= \displaystyle\int\left(1 +\dfrac{7}{2x-2}\right)dx$
$=\displaystyle\int dx + \dfrac72\displaystyle\int\dfrac{2dx}{2x-2}$
$= x +\dfrac72\ln|2x -2| + C$
b) $\displaystyle\int(3x-2)^4dx$
Đặt $u = 3x -2$
$\to du = 3dx$
Ta được:
$\dfrac13\displaystyle\int u^4du$
$=\dfrac{u^5}{15} + C$
$=\dfrac{(3x-2)^5}{15} + C$
