Đặt `A= 1/3 + 1/15 + 1/35 +...+1/255`
`A= 1/1.3 + 1/3.5 + 1/5.7 +...+1/15.17`
`2A= 2(1/1.3 + 1/3.5 + 1/5.7 +...+1/15.17)`
`2A= 2/1.3 + 2/3.5 + 2/5.7 +...+2/15.17`
`2A= 1 -1/3+1/3-1/5+1/5-1/7+...+1/15-1/17`
`2A= 1-1/17`
`2A= 16/17`
`A= 16/17 ;2`
`A= 16/17 .1/2`
`A= 8/17`
Vậy `A= 8/17`