Đáp án+Giải thích các bước giải:
`(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)-2^32`(sửa)
`=1(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)-2^32`
`=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)-2^32`
`=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)-2^32`
`=(2^4-1)(2^4+1)(2^8+1)(2^16+1)-2^32`
`=(2^8-1)(2^8+1)(2^16+1)-2^32`
`=(2^16-1)(2^16+1)-2^32`
`=2^32-1-2^32`
`=-1`