Tính nhanh: \(A = \frac{5}{{1.3}} + \frac{5}{{3.5}} + \frac{5}{{5.7}} + ... + \frac{5}{{99.101}}\)
A.\(A=\frac{{250}}{{101}}\)
B.\(A=\frac{{25}}{{101}}\)
C.\(A=\frac{{25}}{{11}}\)
D.\(A=\frac{{252}}{{11}}\)
A.\(A=\frac{{250}}{{101}}\)
B.\(A=\frac{{25}}{{101}}\)
C.\(A=\frac{{25}}{{11}}\)
D.\(A=\frac{{252}}{{11}}\)
Loga
Hóa Học lớp 12
