$Đáp$ $án$: $\frac{16}{33}$
$Giải$ $thích$ $các$ $bước$ $giải$:
$1$$\frac{1}{3}$ ÷ $1$$\frac{1}{4}$ ÷ $1$$\frac{1}{5}$ ÷ ...... ÷ $1$$\frac{1}{10}$
= $\frac{4}{3}$ ÷ $\frac{5}{4}$ ÷ $\frac{6}{5}$ ÷ .......... ÷ $\frac{11}{10}$
= $\frac{4}{3}$ × $\frac{4}{5}$ × $\frac{5}{6}$ × .......... × $\frac{10}{11}$ ( $bước$ $này$ $bạn$ $triệt$ $tiêu$ $tử$ $và$ $mẫu$ )
= $\frac{4}{3}$ × $\frac{4}{1}$ × $\frac{1}{11}$
= $\frac{16}{33}$
