Đáp án:
$1$
Giải thích các bước giải:
Ta có:
$\qquad \dfrac{1+\dfrac{3}{7}+\dfrac{7}{9}}{3+1\ \dfrac{2}{7}+2\ \dfrac{1}{3}}+\dfrac{2222}{3333}$
$= \dfrac{1+\dfrac{3}{7}+\dfrac{7}{9}}{3+ \dfrac{9}{7}+ \dfrac{7}{3}}+\dfrac{2222:1111}{3333:1111}$
$=\dfrac{1+\dfrac{3}{7}+\dfrac{7}{9}}{3.\ 1+ 3. \dfrac{3}{7}+3. \dfrac{7}{9}}+\dfrac{2}{3}$
$=\dfrac{1+\dfrac{3}{7}+\dfrac{7}{9}}{3.\left(1+ \dfrac{3}{7}+ \dfrac{7}{9}\right)}+\dfrac{2}{3}$
`=1/3+2/3=1`