c) `n_{H_2SO_4}=\frac{0,098}{98}=0,001 \ (mol)`
`H_2SO_4 → 2H^++SO_4^{2-}`
`0,001` `0,002` `(mol)`
`[H^+]=\frac{0,002}{0,2}=0,01 \ (M)`
`pH=-log[H^+]=-log0,01=2`
d) `n_{NaOH}=\frac{0,0012}{40}=0,00003 \ (mol)`
`NaOH \ → \ Na^+ \ + \ OH^-`
`0,00003` `0,00003` `(mol)`
`[OH^-]=\frac{0,00003}{0,3}=0,0001 \ (M)`
`pOH=-log[OH^-]=-log0,0001=4`
`pH=14-pOH=14-4=10`
