a.nK=39/39=1mol
2K+2H2O→2KOH+H2↑
Theo pt :
nH2=1/2.nK=1/2.0,1=0,5mol
nKOH=nK=1mol
⇒mKOH=1.56=56g
mdd spu=39+362−0,5.2=400g
⇒C%KOH=40056=14%
b.nSO3=200/80=2,5mol
mdd H2SO4=1000.1,12=1120g
SO3+H2O→H2SO4
Theo pt :
nH2SO4=nSO3=2,5mol
⇒mH2SO4=1120.17%+2,5.98=435,4g
mdd spu=200+1120=1320g
⇒C%H2SO4=132043,5.100%=33%