Đáp án:
NaNO3 có PTK: 23+14+3.16 = 85 g/mol
%mNa = 23/85.100% = 27,06%
%mN = 14/85.100% = 16,47%
%mO = 100-27,06-16,47 = 56,47%
K2CO3 có PTK: 2.39+12+3.16 = 138 g/mol
% mK = 39x2/138x100% = 56,52%
% mC = 12/138x100% = 8,7%
% mO = 100-56,52-8,7 = 34,78%
Al(OH)3 có PTK: 27+3.(16+1) = 78 g/mol
% mAl = 27/78.100% = 34,62 %
% mO = 3.16/78.100% = 61,54%
% mH = 100-34,62-61,54 = 3,84 %
SO2 có PTK: 32+2.16 = 64 g/mol
% mS = $\frac{32}{64}$ . 100 = 50%
% mO = $\frac{2.16}{64}$ . 100 = 50%
SO3 có PTK: 32+3.16 = 80 g/mol
% mS = $\frac{32}{80}$ . 100 = 40%
% mO = $\frac{3.16}{80}$ . 100 = 60%
Fe2O3 có PTK: 2.56+3.16 = 160 g/mol
% mFe =$\frac{2.56}{160}$ .100 = 70%
% mO = $\frac{3.16}{160}$ .100 = 30 %
