$M_{HCl} = 1 + 35,5 = 36,5 đvC $
$M_{CO_{2}} = 12 + 16.2 = 44 đvC$
$M_{H_{2}O} = 1.2 + 16 = 18 đvC$
$\text{ Trong đó M của các chất như sau : }$
$\text{ H =1 ; Cl = 35,5 ; C = 12 ; O = 16 }$
Đáp án:
$PTK_{HCL}$= 1+35,5=36,5 (đvC)
$PTK_{CO2}$= 12+32=44 (đvC)
$PTK_{H2O}$= 2+16=18 (đvC)
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