Đáp án:
Giải thích các bước giải:
\[\begin{array}{l}
Ta\_co:\\
\frac{1}{{2!}} = \frac{{{2^2} - 3}}{{2!}} = \frac{{{2^2}}}{{2!}} - \frac{3}{{2!}} = \frac{{{2^2}}}{{2!}} - \frac{{{3^2}}}{{3!}}\\
\frac{5}{{3!}} = \frac{{{3^2} - 4}}{{3!}} = \frac{{{3^2}}}{{3!}} - \frac{4}{{3!}} = \frac{{{3^2}}}{{3!}} - \frac{{{4^2}}}{{4!}}\\
...\\
\frac{{9899}}{{100!}} = \frac{{{{100}^2} - 101}}{{100!}} = \frac{{{{100}^2}}}{{100!}} - \frac{{101}}{{100!}} = \frac{{{{100}^2}}}{{100!}} - \frac{{{{101}^2}}}{{101!}}\\
= > Q = \frac{{{2^2}}}{{2!}} - \frac{{{{101}^2}}}{{101!}}
\end{array}\]
