Tính tổng: \(\frac{1}{2} + \frac{1}{4} + \frac{1}{8} + \frac{1}{{16}} + \frac{1}{{64}} + \frac{1}{{128}} + \frac{1}{{256}} + \frac{1}{{512}} + \frac{1}{{1024}}\)
A.\(\frac{{1023}}{{1024}}\)
B.\(\frac{{1026}}{{1027}}\)
C.\(\frac{{1025}}{{1024}}\)
D.\(\frac{{1028}}{{1029}}\)

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