Đáp án:
\(\begin{array}{l}
b)\\
{C_{{M_{Ca{{(OH)}_2}}}}} = 0,5M\\
c)\\
{V_{{H_2}S{O_4}}} = 107,45ml
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
CaO + {H_2}O \to Ca{(OH)_2}\\
Ca{(OH)_2} + {H_2}S{O_4} \to CaS{O_4} + 2{H_2}O\\
b)\\
{n_{CaO}} = \dfrac{m}{M} = \dfrac{{14}}{{56}} = 0,25mol\\
\Rightarrow {n_{Ca{{(OH)}_2}}} = {n_{CaO}} = 0,25mol\\
{C_{{M_{Ca{{(OH)}_2}}}}} = \dfrac{n}{V} = \dfrac{{0,25}}{{0,5}} = 0,5M\\
c)\\
{n_{{H_2}S{O_4}}} = {n_{Ca{{(OH)}_2}}} = 0,25mol\\
{m_{{H_2}S{O_4}}} = n \times M = 0,25 \times 98 = 24,5g\\
{m_{{\rm{dd}}{H_2}S{O_4}}} = \dfrac{{24,5 \times 100}}{{20}} = 122,5g\\
\Rightarrow {V_{{H_2}S{O_4}}} = \dfrac{m}{d} = \dfrac{{122,5}}{{1,14}} = 107,45ml
\end{array}\)
