Giải thích các bước giải:
Ta có:
$\displaystyle\int (10\sin^2x-4\cos^22x)dx$
$=\displaystyle\int (5\cdot 2\sin^2x-2\cdot 2\cos^22x)dx$
$=\displaystyle\int (5(1-\cos2x)-2\cdot (\cos4x+1))dx$
$=\displaystyle\int3-5\cos2x-2\cos4xdx$
$=3x-\dfrac52\sin2x-\dfrac24\sin4x+C$
$=3x-\dfrac52\sin2x-\dfrac12\sin4x+C$