d)
`3x-\frac{1}{4}=\frac{5}{6}`
`⇔3x=\frac{5}{6}+\frac{1}{4}`
`⇔3x=\frac{13}{12}`
`⇔x=\frac{13}{36}`
Vậy `x=\frac{13}{36}`
e)
`\frac{3}{2}-2x=\frac{4}{3} `
`⇔-2x=\frac{4}{3}-\frac{3}{2} `
`⇔-2x=-\frac{1}{6} `
`⇔x=\frac{1}{12} `
Vậy `x=\frac{1}{12} `
f)
`x+\frac{4}{5}=\frac{1}{2}-(-\frac{5}{6})`
`⇔x+\frac{4}{5}=\frac{1}{2}+\frac{5}{6}`
`⇔x=\frac{1}{2}+\frac{5}{6}-\frac{4}{5}`
`⇔x=\frac{8}{15}`
Vậy `x=\frac{8}{15}`
