a, Ta có:
\(\widehat{xOb}\) = 120 \(^{\circ}\)
\(\widehat{xOa}\) = 60 \(^{\circ}\)
=> \(\widehat{xOb}\) > \(\widehat{xOa}\) ( 120 \(^{\circ}\) > 60 \(^{\circ}\))
=> Tia Oa nằm giữa hai tia Ox và Ob
=> \(\widehat{aOb}\) = \(\widehat{xOb}\) - \(\widehat{xOa}\) = 120 \(^{\circ}\) - 60 \(^{\circ}\) = 60\(^{\circ}\)
b, Ta có:
\(\widehat{xOa}\) + \(\widehat{aOb}\) + \(\widehat{tOb}\) + \(\widehat{tOy}\) = 180 \(^{\circ}\)
hay 2. \(\widehat{aOb}\) + 2. \(\widehat{tOb}\) = 180 \(^{\circ}\)
=> 2 ( \(\widehat{aOb}\) + \(\widehat{tOb}\) ) = 180 \(^{\circ}\)
=> \(\widehat{aOb}\) + \(\widehat{tOb}\) = 90 \(^{\circ}\)
=> \(\widehat{aOt}\) = 90 \(^{\circ}\)