Em tham khảo nha :
\(\begin{array}{l}
a)\\
2NaOH + CuS{O_4} \to Cu{(OH)_2} + N{a_2}S{O_4}\\
{m_{NaOH}} = \dfrac{{300 \times 8}}{{100}} = 24g\\
{n_{NaOH}} = \dfrac{{24}}{{40}} = 0,6mol\\
{n_{Cu{{(OH)}_2}}} = \dfrac{{{n_{NaOH}}}}{2} = 0,3mol\\
{m_{Cu{{(OH)}_2}}} = 0,3 \times 98 = 29,4g\\
b)\\
Cu{(OH)_2} \to CuO + {H_2}O\\
{n_{CuO}} = {n_{Cu{{(OH)}_2}}} = 0,3mol\\
{m_{CuO}} = 0,3 \times 80 = 24g\\
{n_{CuS{O_4}}} = \dfrac{{{n_{NaOH}}}}{2} = 0,3mol\\
{m_{CuS{O_4}}} = 0,3 \times 160 = 48g\\
{m_{{\rm{dd}}CuS{O_4}}} = \dfrac{{48 \times 100}}{{16}} = 300g\\
{n_{N{a_2}S{O_4}}} = \dfrac{{{n_{N{a_2}S{O_4}}}}}{2} = 0,3mol\\
{m_{N{a_2}S{O_4}}} = 0,3 \times 142 = 42,6g\\
C{\% _{N{a_2}S{O_4}}} = \dfrac{{42,6}}{{300 + 300 - 29,4}} \times 100\% = 7,47\%
\end{array}\)
