A.\(\dfrac{{x + 1}}{1} = \dfrac{{y - 3}}{{ - \,2}} = \dfrac{{z + 1}}{2}.\)B. \(\dfrac{{x + 1}}{1} = \dfrac{{y - 8}}{{ - \,2}} = \dfrac{{z - 4}}{2}.\)C. \(\dfrac{{x + \dfrac{1}{3}}}{1} = \dfrac{{y - \dfrac{5}{3}}}{{ - \,2}} = \dfrac{{z - \dfrac{{11}}{6}}}{2}.\)D. \(\dfrac{{x + \dfrac{2}{9}}}{1} = \dfrac{{y - \dfrac{2}{9}}}{{ - \,2}} = \dfrac{{z + \dfrac{5}{9}}}{2}.\)
B.
C.
D.
Loga
Hóa Học lớp 12
