a/ \(Zn+2HCl\longrightarrow ZnCl_2+H_2↑(1)\\Zn+H_2SO_4\longrightarrow ZnSO_4+H_2↑(2)\\Fe+H_2SO_4\longrightarrow FeSO_4+H_2↑\\Fe+HCl\longrightarrow FeCl_2+H_2↑\)
b/ \(∑n_{H_2}=\dfrac{2,24}{22,4}=0,1(mol)\)
\(→∑n_{Zn}=0,1(mol)\)
\(→m_{Zn}=0,1.65=6,5(g)\)
\(∑n_{H_2}=0,1(mol)\)
\(→∑n_{Fe}=0,1(mol)\)
\(→m_{Fe}=0,1.56=5,6(g)\)