$n_{KMnO4}=63,2/158=0,4mol$
$2KMnO4\overset{t^o}\to K2MnO4+MnO2+O2$
$1/$
$\text{Theo pt :}$
$n_{O_2}=1/2.n_{KMnO4}=1/2.0,4=0,2mol$
$⇒V_{O_2}=0,2.22,4=4,48l$
$2/$
$a/n_P=3,1/31=0,1mol$
$4P + 5O_2\overset{t^o}\to 2P2O5$
$\text{Theo pt : 4 mol 5mol}$
$\text{Theo đbài :0,1mol 0,2mol}$
$\text{⇒Sau pư O2 dư 0,075mol}$
$b/$
$\text{Theo pt :}$
$n_{P_2O_5}=1/2.n_P=1/2.0,1=0,05mol$
$⇒m_{P_2O_5}=0,05.142=7,1g$