Bài 1:
a) Độ tụ:
\(D = \dfrac{1}{f} = \dfrac{1}{{0,2}} = 5dp\)
b) Ta có:
\(\begin{array}{l}
\dfrac{1}{f} = \dfrac{1}{d} + \dfrac{1}{{d'}} \Rightarrow \dfrac{1}{{20}} = \dfrac{1}{d} - \dfrac{1}{{d + 18}}\\
\Rightarrow d = 12cm \Rightarrow d' = - 30cm
\end{array}\)
Bài 2:
* TH1: Ảnh thật:
\(\begin{array}{l}
\dfrac{{d'}}{d} = 2 \Rightarrow d' = 2d\\
\dfrac{1}{f} = \dfrac{1}{d} + \dfrac{1}{{d'}} \Rightarrow \dfrac{1}{{10}} = \dfrac{1}{d} + \dfrac{1}{{2d}} \Rightarrow d = 15cm
\end{array}\)
* TH2: Ảnh ảo:
\(\begin{array}{l}
\dfrac{{d'}}{d} = - 2 \Rightarrow d' = - 2d\\
\dfrac{1}{f} = \dfrac{1}{d} + \dfrac{1}{{d'}} \Rightarrow \dfrac{1}{{10}} = \dfrac{1}{d} - \dfrac{1}{{2d}} \Rightarrow d = 5cm
\end{array}\)