Vi phân của $y=\tan 5x$ là :
A.$\text{d}y=\dfrac{-5}{{{\sin }^{2}}5x}\text{d}x.$
B.$\text{d}y=\dfrac{5x}{{{\cos }^{2}}5x}\text{d}x.$
C.$\text{d}y=\dfrac{-5}{{{\cos }^{2}}5x}\text{d}x.$
D.$\text{d}y=\dfrac{5}{{{\cos }^{2}}5x}\text{d}x.$
A.$\text{d}y=\dfrac{-5}{{{\sin }^{2}}5x}\text{d}x.$
B.$\text{d}y=\dfrac{5x}{{{\cos }^{2}}5x}\text{d}x.$
C.$\text{d}y=\dfrac{-5}{{{\cos }^{2}}5x}\text{d}x.$
D.$\text{d}y=\dfrac{5}{{{\cos }^{2}}5x}\text{d}x.$
Loga
Hóa Học lớp 12
