Em tham khảo nha:
\(\begin{array}{l}
*\\
2HCl \to {H_2} + C{l_2}\\
Mn{O_2} + 4HCl \to MnC{l_2} + C{l_2} + 2{H_2}O\\
2KMn{O_4} + 16HCl \to 2KCl + 2MnC{l_2} + 5C{l_2} + 8{H_2}O\\
KCl{O_3} + 6HCl \to KCl + 3C{l_2} + 3{H_2}O\\
HClO + HCl \to C{l_2} + {H_2}O\\
*\\
C{l_2} + S{O_2} + 2{H_2}O \to 2HCl + {H_2}S{O_4}\\
C{l_2} + {H_2} \to 2HCl\\
C{l_2} + {H_2}O \to HCl + HClO\\
4C{l_2} + {H_2}S + 4{H_2}O \to {H_2}S{O_4} + 8HCl\\
B{r_2} + 5C{l_2} + 6{H_2}O \to 2HBr{O_3} + 10HCl
\end{array}\)