Đáp án:
\(\begin{array}{l}
Mg + 2HCl \to MgC{l_2} + {H_2}\\
Mg + {H_2}S{O_4} \to MgS{O_4} + {H_2}\\
Zn + 2HCl \to ZnC{l_2} + {H_2}\\
Zn + {H_2}S{O_4} \to ZnS{O_4} + {H_2}\\
2Al + 6HCl \to 2AlC{l_3} + 3{H_2}\\
2Al + 3{H_2}S{O_4} \to A{l_2}{(S{O_4})_3} + 3{H_2}\\
Fe + 2HCl \to FeC{l_2} + {H_2}\\
Fe + {H_2}S{O_4} \to FeS{O_4} + {H_2}
\end{array}\)