Đáp án:

Bạn tham khảo lời giải ở dưới nhé!!

Giải thích các bước giải:

\(\begin{array}{l}
HN{O_3} \to {H^ + } + N{O_3}^ - \\
Fe{(N{O_3})_3} \to F{e^{3 + }} + 3N{O_3}^ - \\
NaF \to N{a^ + } + {F^ - }\\
CaC{l_2} \to C{a^{2 + }} + 2C{l^ - }\\
Ca{(N{O_3})_2} \to C{a^{2 + }} + 2N{O_3}^ - \\
{H_2}S \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {H^ + } + H{S^ - }\\
H{S^ - } \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {H^ + } + {S^{2 - }}\\
CuS{O_4} \to C{u^{2 + }} + S{O_4}^{2 - }\\
AlC{l_3} \to A{l^{3 + }} + 3C{l^ - }\\
KN{O_3} \to {K^ + } + N{O_3}^ - \\
N{a_2}C{O_3} \to 2N{a^ + } + C{O_3}^{2 - }\\
C{H_3}COOH \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} C{H_3}CO{O^ - } + {H^ + }\\
NaHC{O_3} \to N{a^ + } + HC{O_3}^ - \\
{K_2}S{O_4} \to 2{K^ + } + S{O_4}^{2 - }\\
N{H_4}Cl \to N{H_4}^ +  + C{l^ - }\\
HClO \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {H^ + } + Cl{O^ - }\\
{K_2}C{O_3} \to 2{K^ + } + C{O_3}^{2 - }\\
N{a_2}S \to 2N{a^ + } + {S^{2 - }}\\
CuC{l_2} \to C{u^{2 + }} + 2C{l^ - }\\
{K_3}P{O_4} \to 3{K^ + } + P{O_4}^{3 - }\\
ZnC{l_2} \to Z{n^{2 + }} + 2C{l^ - }\\
NaHS \to N{a^ + } + H{S^ - }\\
H{S^ - } \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {H^ + } + {S^{2 - }}\\
MgC{l_2} \to M{g^{2 + }} + 2C{l^ - }\\
KCl \to {K^ + } + C{l^ - }\\
Ca{(HC{O_3})_2} \to C{a^{2 + }} + 2HC{O_3}^ - \\
{(N{H_4})_2}S{O_4} \to 2N{H_4}^ +  + S{O_4}^{2 - }\\
HN{O_3} \to {H^ + } + N{O_3}^ - \\
N{a_3}P{O_4} \to 3N{a^ + } + P{O_4}^{3 - }\\
N{a_2}HP{O_4} \to 2N{a^ + } + HP{O_4}^{2 - }\\
HP{O_4}^{2 - } \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {H^ + } + P{O_4}^{3 - }\\
HN{O_2} \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {H^ + } + N{O_2}^ - \\
F{e_2}{(S{O_4})_3} \to 2F{e^{3 + }} + 3S{O_4}^{2 - }\\
BaC{l_2} \to B{a^{2 + }} + 2C{l^ - }\\
Ca{F_2} \to C{a^{2 + }} + 2{F^ - }\\
{H_3}P{O_4} \to {H^ + } + {H_2}P{O_4}^ - \\
{H_2}P{O_4}^ -  \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {H^ + } + HP{O_4}^{2 - }\\
HP{O_4}^{2 - } \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {H^ + } + P{O_4}^{3 - }\\
{K_2}S{O_3} \to 2{K^ + } + S{O_3}^{2 - }\\
MgC{l_2} \to M{g^{2 + }} + 2C{l^ - }\\
NaCl \to N{a^ + } + C{l^ - }
\end{array}\)