Đáp án:
Giải thích các bước giải:
$a/$
$C_2H_4 + H_2O \xrightarrow{t^o,H^+} C_2H_5OH$
$C_2H_5OH + O_2 \xrightarrow{xt} CH_3COOH + H_2O$
$CH_3COOH + C_2H_5OH ⇄ CH_3COOC_2H_5 + H_2O$
$CH_3COOC_2H_5 + H_2O ⇄ CH_3COOH + C_2H_5OH$
$2CH_3COOH + K_2CO_3 → 2CH_3COOK + CO_2 + H_2O$
$b/$
$CaCO_3 \xrightarrow{t^o} CaO + CO_2$
$CO_2 + NaOH → NaHCO_3$
$NaHCO_3 + NaOH → Na_2CO_3 + H_2O$
$Na_2CO_3 + H_2SO_4 → Na_2SO_4 + CO_2 + H_2O$
$c/$
$(-C_6H_{10}O_5-)_n + nH_2O \xrightarrow{t^o,xt} nC_6H_{12}O_6$
$C_6H_{12}O_6 \xrightarrow{t^o,xt} 2CO_2 + 2C_2H_5OH$
$C_2H_5OH + O_2 \xrightarrow{xt} CH_3COOH + H_2O$
$CH_3COOH + C_2H_5OH ⇄ CH_3COOC_2H_5 + H_2O$
$CH_3COOC_2H_5 + NaOH → CH_3COONa + C_2H_5OH$
$CH_3COONa + HCl → CH_3COOH + NaCl$
$2CH_3COOH + K_2CO_3 → 2CH_3COOK + CO_2 + H_2O$
$CO_2 + Ca(OH)_2 → CaCO_3 + H_2O$
