`(y-2)^3 - (y-3)(y^2 +3y +9) +6(y+1)^2 =49`
`=> (y-2)^3 - (y^3 - 3^3) +6(y^2 +2y +1) =49`
`=> y^3 -6y^2 +12y -8 - y^3 +27 + 6y^2 + 12y +6 =49`
`=> (y^3 -y^3) + (-6y^2 +6y^2) +(12y +12y) + (-8 +27 +6) = 49`
`=> 24y +25 =49`
`=> 24y = 24`
`=> y =1`
Vậy `y =1` .