`-1 1/2 - x = ( - 2 )/3 + 0,75`
`⇔ ( - 3 )/2 - x = ( - 2 )/3 + 3/4`
`⇔ ( - 3 )/2 - x = 1/12`
`⇔ x = ( - 3 )/2 - 1/12`
`⇔ x = ( - 19 )/12`
Vậy , `x = ( - 19 )/12`
_____________________________________
`| 4/5 - x | - 1/10 = 2/5`
`⇔ | 4/5 - x | = 2/5 + 1/10`
`⇔ | 4/5 - x | = 1/2`
Trường hợp `1 : 4/5 - x = 1/2`
`⇔ x = 4/5 - 1/2`
`⇔ x = 3/10`
Trường hợp `2 : 4/5 - x = ( - 1 )/2`
`⇔ x = 4/5 - ( - 1 )/2`
`⇔ x = 13/10`
Vậy , `x ∈ { 3/10 ; 13/10 }`
