Đáp án+Giải thích các bước giải:

$(\dfrac{1}{2}x-\dfrac{2}{3})-1=\dfrac{1}{6}$
$⇒\dfrac{1}{2}x-\dfrac{2}{3}=\dfrac{7}{6}$
$⇒\dfrac{1}{2}x=\dfrac{11}{6}$
$⇒x=\dfrac{11}{3}$
Vậy $x=\dfrac{11}{3}$
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$(x-\dfrac{3}{5}).\dfrac{1}{2}-1.5=0$
$⇒(x-\dfrac{3}{5}).\dfrac{1}{2}=5$
$⇒x-\dfrac{3}{5}=10$
$⇒x=\dfrac{53}{5}$
Vậy $x=\dfrac{53}{5}$

($\frac{1}{2}$. $x^{}$ - $\frac{2}{3}$) - 1 = $\frac{1}{6}$

($\frac{1}{2}$. $x^{}$ - $\frac{2}{3}$) = $\frac{1}{6}$ + 1

($\frac{1}{2}$. $x^{}$ - $\frac{2}{3}$) = $\frac{1}{6}$ + $\frac{6}{6}$

($\frac{1}{2}$. $x^{}$ - $\frac{2}{3}$) = $\frac{7}{6}$

($\frac{1}{2}$. $x^{}$) = $\frac{7}{6}$ + $\frac{2}{3}$

($\frac{1}{2}$. $x^{}$) = $\frac{7}{6}$ + $\frac{4}{6}$

$\frac{1}{2}$. $x^{}$ = $\frac{11}{6}$

$x^{}$ = $\frac{11}{6}$ : $\frac{1}{2}$

$x^{}$ = $\frac{11}{6}$ . $\frac{2}{1}$

$x^{}$ = $\frac{11}{3}$ (Rút gọn 6 với 2 [6:2 = 3])

($x^{}$ - $\frac{3}{5}$). $\frac{1}{2}$ - 1,5 = 0

($x^{}$ - $\frac{3}{5}$). $\frac{1}{2}$ = 0 + 1,5

($x^{}$ - $\frac{3}{5}$). $\frac{1}{2}$ = 1,5

($x^{}$ - $\frac{3}{5}$) = 1,5 : $\frac{1}{2}$

($x^{}$ - $\frac{3}{5}$) = $\frac{15}{10}$ : $\frac{1}{2}$

($x^{}$ - $\frac{3}{5}$) = $\frac{15}{10}$ . $\frac{2}{1}$

$x^{}$ - $\frac{3}{5}$ = 3 (Rút gọn 10 và 2 [10:2 = 5 => $\frac{15}{5}$ = 3 [15:5 =3])

$x^{}$ = 3 + $\frac{3}{5}$

$x^{}$ = 3$\frac{3}{5}$