TH1 : `x-3 = 6 `
`x=6+3 `
`x=9 `
TH2 : `x-3 = -6 `
`x=-6+3 `
`x=-3 `
vậy `x\in{9;=3}`
`12-|x|=8`
`|x| = 12 - 8 `
`|x|=4 `
`x=4;-4 `
vậy `x\in{4;-4}`
`(x-2/3)^2 = 5/6 `
`(x-2/3) = `$\sqrt{\dfrac{5}{6}}$
TH1 ` x = `$\sqrt{\dfrac{5}{6}}$`+ 2/3 `
TH2 : ` x = `$-\sqrt{\dfrac{5}{6}}$`+ 2/3 `
vậy `x\in{` $ \pm\sqrt{\dfrac{5}{6} + \dfrac{2}{3}}$
`(3/4 - x )^3 = -8`
`(3/4-x)^3=(-2)^3`
`3/4 - x = -2 `
`x=3/4 - (-2)`
`x=3/4 + 2 `
`x=11/4`
