Đáp án:
Giải thích các bước giải:
$1)-25x^6 - y^8 + 10x^3y^4$
$=-(25x^6 - 10x^3y^4 + y^8)$
$=-(5x^3 - y^4)$
$2)(x + y)^2 - 25$
$=(x + y - 5)(x + y + 5)$
$3)27 + 27x + 9x^2 + x^3$
$=(x+3)^3$
$4)1 - 4x^2$
$=-(4x^2 - 1)$
$=-(2x - 1)(2x + 1)$
$5)x^6 - x^4 + 2x^3 + 2x^2$
$=(x^3 + x^2)(x^3 - x^2) + 2x^2(x + 1)$
$=x^2(x + 1)(x^3 - x^2) + 2x^2(x + 1)$
$=(x + 1)(x^5 - x^6 + 2x^2)$
$=(x + 1)x^2(x^3 - x^4 + 2)$
$6)4x^2 + 12x + 9$
$=(2x + 3)^2$
$7)x^4 + 64$
$=(x^4 + 16x^2 + 64) - 16x^2$
$=(x^2 + 8) - 16x^2$
$=(x^2 + 8 + 4x)(x^2 + 8 - 4x)$
$8)x^2 - xy - 8x + 8y$
$=x(x - y) - 8(x - y)$
$=(x - 8)(x - y)$
$10)8 - 27x^3$
$=-(3x - 2)(9x^2 + 6x + 4)$
