`(|x| + 1/3)^2 - 0,375 = (-1/2)^3`
`⇒ (|x|+1/3)^2 - 0,375 = -1/8`
`⇒ (|x|+1/3)^2 = -1/8+0,375`
`⇒ (|x|+1/3)^2 = 0,25`
`⇒ (|x|+1/3)^2 = (±0,5)^2`
`⇒ |x| + 1/3 = ±0,5`
$⇒ \left[ \begin{array}{l}|x|+\dfrac{1}{3}=0,5\\|x|+\dfrac{1}{3}=-0,5\end{array} \right.$
$⇒ \left[ \begin{array}{l}|x|=\dfrac{1}{6}\\|x|=\dfrac{5}6\end{array} \right.$
$⇒ \left[ \begin{array}{l}\left[ \begin{array}{l}x=\dfrac{1}{6}\\x=-\dfrac{1}6\end{array} \right. \\\left[ \begin{array}{l}x=\dfrac{5}6\\x=-\dfrac{5}6\end{array} \right. \end{array} \right.$
Vậy `x={1/6;-1/6;5/6;-5/6}`
Xin hay nhất !
