Đáp án:
$x=\dfrac{6}{11}$
Giải thích các bước giải:
$\dfrac{1}{3}x+\dfrac{2}{5}(x-1)=0$
$\dfrac{1}{3}x+\dfrac{2}{5}.x-\dfrac{2}{5}.1=0$
$\dfrac{1}{3}x+\dfrac{2}{5}x-\dfrac{2}{5}=0$
$(\dfrac{1}{3}+\dfrac{2}{5})x=\dfrac{2}{5}$
$\dfrac{11}{15}x=\dfrac{2}{5}$
$x=\dfrac{2}{5}:\dfrac{11}{15}$
$x=\dfrac{2}{5}\cdot\dfrac{15}{11}$
$x=\dfrac{6}{11}$
Vậy $x=\dfrac{6}{11}$
