Đáp án:
Giải thích các bước giải:
`1,|x+4/9|=11/18`
`=>` \(\left[ \begin{array}{l}x+\dfrac{4}{9}=\dfrac{11}{18}\\x+\dfrac{4}{9}=-\dfrac{11}{18}\end{array} \right.\) `=>` \(\left[ \begin{array}{l}x=\dfrac{1}{6}\\x=-\dfrac{19}{18}\end{array} \right.\)
Vậy `x\in{-19/18;1/6}`
`2,5/7-x=-2/4 - -4/63`
`=>5/7-x=-55/126`
`=>x=5/7-(-55/126)`
`=>x=145/126`
Vậy `x=145/126`
`3,|x-25/34|-3/11=2/3`
`=>|x-25/34|=31/33`
`=>` \(\left[ \begin{array}{l}x-\dfrac{25}{34}=\dfrac{31}{33}\\x-\dfrac{25}{34}=-\dfrac{31}{33}\end{array} \right.\) `=>` \(\left[ \begin{array}{l}x=\dfrac{1879}{1122}\\x=-\dfrac{229}{1122}\end{array} \right.\)
Vậy `x\in{-229/1122;1879/1122}`
