Đáp án + Giải thích các bước giải:
$a)x-\dfrac{1}{5}=\dfrac{3}{5}$
$⇒x=\dfrac{3}{5}+\dfrac{1}{5}$
$⇒x=\dfrac{4}{5}$
Vậy $x=\dfrac{4}{5}$
$b)|x-2|-3=5$
$⇒|x-2|=5+3$
$⇒|x-2|=7$
\(⇒\left[ \begin{array}{l}x-2=7\\x-2=-7\end{array} \right.\)
\(⇒\left[ \begin{array}{l}x=7+2\\x=-7+2\end{array} \right.\)
\(⇒\left[ \begin{array}{l}x=9\\x=-5\end{array} \right.\)
Vậy $x=9,x=-5$
$c)-\dfrac{12}{13}.x-5=6\dfrac{1}{13}$
$⇒-\dfrac{12}{13}.x=\dfrac{79}{13}+5$
$⇒-\dfrac{12}{13}.x=\dfrac{144}{13}$
$⇒x=\dfrac{144}{13}:-\dfrac{12}{13}$
$⇒x=\dfrac{144}{13}.-\dfrac{13}{12}$
$⇒x=12$
Vậy $x=12$
$d)3x-\dfrac{4}{2}=\dfrac{1}{3}$
$⇒3x-2=\dfrac{1}{3}$
$⇒3x=\dfrac{1}{3}+2$
$⇒3x=\dfrac{7}{3}$
$⇒x=\dfrac{7}{3}:3$
$⇒x=\dfrac{7}{9}$
Vậy $x=\dfrac{7}{9}$
