|x+$\frac{1}{6}$ |+$\frac{1}{2}$ =$\frac{2}{3}$
|x+$\frac{1}{6}$ | =$\frac{2}{3}$ -$\frac{1}{2}$
|x+$\frac{1}{6}$ | =$\frac{1}{6}$
⇒x+$\frac{1}{6}$ =$\frac{1}{6}$ hoặc x+$\frac{1}{6}$ =-$\frac{1}{6}$
TH1: x+$\frac{1}{6}$ =$\frac{1}{6}$
x=$\frac{1}{6}$ -$\frac{1}{6}$
x=0
TH2. x+$\frac{1}{6}$ =-$\frac{1}{6}$
x=-$\frac{1}{6}$ -$\frac{1}{6}$
x= -$\frac{1}{3}$