Đáp án:
1/
b/ $CH_{3}-C=CH-C=CH_{2}$
penta-1,3-đien
c/
$CH_{2}=CH-CH-CH_{3}$
but-1-en
2/
a/
$CH_{3}-CH(CH_{3})-C(CH_{3})_{2}-CH_{2}-CH_{2}-CH_{3}$
b/ $CH_{2} =CH-C(CH_{3})_{2}-CH_{3}$
c/ $CH_{3}-CH(CH_{3})-(CH_{3})C(C_{2}H_{5})-C-CH_{3}$
3/
a/$CH_{4} + Cl_{2} \buildrel{{as}}\over\longrightarrow CH_{3}Cl +HCl$
Giải thích các bước giải: